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EMP
Joined: 26 May 2005 Posts: 628 BNet Acct/Realm: sequences (Ladder-USEast)
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Posted: Sat Jan 28, 2006 7:10 pm Post subject:
I need some help with Calculus *UPDATED QUESTION |
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how would you take the inverse of
f(x)= 2x^4 - 3x + 5
what is the answer and how did you get it. thanks
EDIT:
what are accumulation functions? (used in calc classes, nothing of that money thing because I tried googling it. )
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Last edited by EMP on Sun Jan 29, 2006 4:43 pm; edited 1 time in total
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OSA
Joined: 11 Dec 2004 Posts: 1139 BNet Acct/Realm: O-S-A on East NL
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Posted: Sat Jan 28, 2006 11:10 pm Post subject:
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Isn't the inverse just 1 over all that?
I dunno.
www.math.com
Check there, they might have it.
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krajee
Joined: 27 Aug 2004 Posts: 6579
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Posted: Sat Jan 28, 2006 11:50 pm Post subject:
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OSA wrote: | Isn't the inverse just 1 over all that? |
Thats reciprocal. Inverse is f^-1(x).
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lld_master
Joined: 04 Oct 2004 Posts: 412
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Posted: Sun Jan 29, 2006 3:49 am Post subject:
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all you have to do is switch the X and the Y and then again make it all equal to Y.
Meaning,
it is:
f(x) = 2x^4 - 3x +5
Y = 2x^4 - 3x +5
X = 2Y^4 - 3Y +5
(X - 5 + 3y) = 2Y^4
(X - 5 + 3y)/2 = Y^4
Y = foruthrootof((X - 5 + 3y)/2)
answer:
y = foruthrootof((X - 5 + 3Y)/2)
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EMP
Joined: 26 May 2005 Posts: 628 BNet Acct/Realm: sequences (Ladder-USEast)
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Posted: Sun Jan 29, 2006 4:42 am Post subject:
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I can just leave it like that? Don't I have to put all of the 'y's on one side or something? But ((x - 5 + 3y)/2)^(1/4) = y sounds like a plausible answer. The only problem I have with it is that if I were to attempt tio graph it, how would I be able to plug in the y-values if I don't know it?
Thanks
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B[x]
Joined: 04 May 2004 Posts: 6130 BNet Acct/Realm: Retired
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Posted: Sun Jan 29, 2006 12:09 pm Post subject:
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lld_master wrote: | answer:
y = foruthrootof((X - 5 + 3Y)/2) |
y = (x - 5)/(2y^3 - 3) is a bit neater but to each his own.
As for graphing it, it's been awhile since I took Calculus I so I'm not sure on the rules of inverses anymore, sorry.
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LLD_Pie
Joined: 22 Jun 2004 Posts: 515
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Posted: Sun Jan 29, 2006 12:58 pm Post subject:
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to graph it first find its intercepts
so set y to 0 and you get
if y = 0 then x = 5 because 0 / anyting = 0
if y = 1 then
1 = (x-5)/(2-3)
1 = (x-5)/(-1)
-1 = x-5
x = 4
if y = 2 then
2 = (x-5)/(13)
16 = (x-5)
x = 21
if y = -1 then
-1 = (x-5)/(-5)
5 = (x -5)
x = 10
somone check me on this but im pretty sure thats how its done...
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B[x]
Joined: 04 May 2004 Posts: 6130 BNet Acct/Realm: Retired
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Posted: Sun Jan 29, 2006 1:02 pm Post subject:
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OHHHHHHHHH!! For some reason I thought he wanted it in y= form so that he could plug it into his calculator for an easy quick graph. Oh, okay. Yeah, to graph it by hand (if that's what you want to do), just pick arbitrary y-values and solve for x.
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EMP
Joined: 26 May 2005 Posts: 628 BNet Acct/Realm: sequences (Ladder-USEast)
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Posted: Sun Jan 29, 2006 1:33 pm Post subject:
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ahh, thanks so much guys.
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ATOMICMAN
Official LLD101 Drunkard
Joined: 01 Mar 2004 Posts: 2740 BNet Acct/Realm: *ATOMICMAN-LLD USEastNL Retired
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Posted: Sun Jan 29, 2006 5:11 pm Post subject:
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god i hated calc =(
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Royale
Joined: 22 Sep 2005 Posts: 702 BNet Acct/Realm: Battle_Royale, Battle-Royale (US East)
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Posted: Sun Jan 29, 2006 5:31 pm Post subject:
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I got kind of dizzy reading this thread.
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Visual Tactics
LLD101 Staff
Joined: 01 Jan 2006 Posts: 2744 BNet Acct/Realm: West NL
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Posted: Sun Jan 29, 2006 5:32 pm Post subject:
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Uh oh, i'm taking calc next year...
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lld_master
Joined: 04 Oct 2004 Posts: 412
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Posted: Sun Jan 29, 2006 6:06 pm Post subject:
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to graph this using a calculator would be easy since there is an Inverse function on the TI-83
for example it would be something like this:
y1=Inverse(2x^4 - 3x +5)
done!
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krajee
Joined: 27 Aug 2004 Posts: 6579
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Posted: Sun Jan 29, 2006 6:20 pm Post subject:
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lld_master wrote: | to graph this using a calculator would be easy since there is an Inverse function on the TI-83 |
The TI-83 only graphs functions, although I think there are programs you can add to change that.
_________________ " 'You miss 100% of the shots you don’t take' - Wayne Gretzky " - Michael Scott
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B[x]
Joined: 04 May 2004 Posts: 6130 BNet Acct/Realm: Retired
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Posted: Sun Jan 29, 2006 11:06 pm Post subject:
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lld_master wrote: | to graph this using a calculator would be easy since there is an Inverse function on the TI-83
for example it would be something like this:
y1=Inverse(2x^4 - 3x +5)
done! |
I whipped out my old TI-83+ and the only thing I found was a InvNorm function. When I plotted it, it gave me a weird scatter of points. I pulled out my TI-89 Titanium (which is what I use for my classes - required) and after another quick search, couldn't even find any sort of Inverse function. Oh well, most of the stuff I do now is either conceptual or requires a program like Mathematica to do.
Gheed wrote: | The TI-83 only graphs functions, although I think there are programs you can add to change that. |
Wouldn't doubt it at all.
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